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mass of the Earth

Generated by the Physics Derivation Graph. Eq. \ref{eq:3843242} is an initial equation. \begin{equation} F = m a \label{eq:3843242} \end{equation} Change variable \(a\) to \(g\) in Eq. \ref{eq:3843242}; yields Eq. \ref{eq:6779814}. \begin{equation} F = m g \label{eq:6779814} \end{equation} Change variable \(g\) to \(g_{\rm Earth}\) in Eq. \ref{eq:6779814}; yields Eq. \ref{eq:6086107}. \begin{equation} F = m g_{\rm Earth} \label{eq:6086107} \end{equation} Eq. \ref{eq:2737346} is an initial equation. \begin{equation} F = G \frac{m_1 m_2}{x^2} \label{eq:2737346} \end{equation} Change of variable \(m_1\) to \(m_{\rm Earth}\) and \(m_2\) to \(m\) and \(x\) to \(r_{\rm Earth}\) in Eq. \ref{eq:2737346}; yields Eq. \ref{eq:6771172}. \begin{equation} F = G \frac{m_{\rm Earth} m}{r_{\rm Earth}^2} \label{eq:6771172} \end{equation} LHS of Eq. \ref{eq:6771172} is equal to LHS of Eq. \ref{eq:6086107}; yields Eq. \ref{eq:7388891}. \begin{equation} G \frac{m_{\rm Earth} m}{r_{\rm Earth}^2} = m g_{\rm Earth} \label{eq:7388891} \end{equation} Divide both sides of Eq. \ref{eq:7388891} by \(m\); yields Eq. \ref{eq:9159337}. \begin{equation} G \frac{m_{\rm Earth}}{r_{\rm Earth}^2} = g_{\rm Earth} \label{eq:9159337} \end{equation} Multiply both sides of Eq. \ref{eq:9159337} by \(\frac{r_{\rm Earth}^2}{G}\); yields Eq. \ref{eq:9133599}. \begin{equation} m_{\rm Earth} = \frac{g_{\rm Earth} r_{\rm Earth}^2}{G} \label{eq:9133599} \end{equation} Replace constant \(g_{\rm Earth}\) with value \(9.80665\) and units \(m/s^2\) in Eq. \ref{eq:9133599}; yields Eq. \ref{eq:2593741} \begin{equation} m_{\rm Earth} = \frac{(9.80665 m/s^2) r_{\rm Earth}^2}{G} \label{eq:2593741} \end{equation} Replace constant \(G\) with value \(6.67430*10^{-11}\) and units \(m^3 kg^{-1} s^{-2}\) in Eq. \ref{eq:2593741}; yields Eq. \ref{eq:1218257} \begin{equation} m_{\rm Earth} = \frac{(9.80665 m/s^2) r_{\rm Earth}^2}{6.67430*10^{-11}m^3 kg^{-1} s^{-2}} \label{eq:1218257} \end{equation} Replace constant \(r_{\rm Earth}\) with value \(6.3781*10^6\) and units \(m\) in Eq. \ref{eq:1218257}; yields Eq. \ref{eq:9815516} \begin{equation} m_{\rm Earth} = \frac{(9.80665 m/s^2) (6.3781*10^6 m)^2}{6.67430*10^{-11}m^3 kg^{-1} s^{-2}} \label{eq:9815516} \end{equation} Simplify Eq. \ref{eq:9815516}; yields Eq. \ref{eq:1635641}. \begin{equation} m_{\rm Earth} = 5.972*10^{24} kg \label{eq:1635641} \end{equation}